2[z-(7z+17)+5]=3(z+2)

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Solution for 2[z-(7z+17)+5]=3(z+2) equation:


Simplifying
2[z + -1(7z + 17) + 5] = 3(z + 2)

Reorder the terms:
2[z + -1(17 + 7z) + 5] = 3(z + 2)
2[z + (17 * -1 + 7z * -1) + 5] = 3(z + 2)
2[z + (-17 + -7z) + 5] = 3(z + 2)

Reorder the terms:
2[-17 + 5 + z + -7z] = 3(z + 2)

Combine like terms: -17 + 5 = -12
2[-12 + z + -7z] = 3(z + 2)

Combine like terms: z + -7z = -6z
2[-12 + -6z] = 3(z + 2)
[-12 * 2 + -6z * 2] = 3(z + 2)
[-24 + -12z] = 3(z + 2)

Reorder the terms:
-24 + -12z = 3(2 + z)
-24 + -12z = (2 * 3 + z * 3)
-24 + -12z = (6 + 3z)

Solving
-24 + -12z = 6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-24 + -12z + -3z = 6 + 3z + -3z

Combine like terms: -12z + -3z = -15z
-24 + -15z = 6 + 3z + -3z

Combine like terms: 3z + -3z = 0
-24 + -15z = 6 + 0
-24 + -15z = 6

Add '24' to each side of the equation.
-24 + 24 + -15z = 6 + 24

Combine like terms: -24 + 24 = 0
0 + -15z = 6 + 24
-15z = 6 + 24

Combine like terms: 6 + 24 = 30
-15z = 30

Divide each side by '-15'.
z = -2

Simplifying
z = -2

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